x/2 + y/3 = 5, x - y/2 = 4

Frequently Asked Questions

• Solve using the substitution method of $x/2+y/3=5,x-y/2=4$

  

  $$\left(x,y\right)=\left(\frac{46}{7},\frac{36}{7}\right)$$

• Solve using the elimination method of $x/2+y/3=5,x-y/2=4$

  

  $$\left(x,y\right)=\left(\frac{46}{7},\frac{36}{7}\right)$$

• Solve using the Gauss-Jordan method of $x/2+y/3=5,x-y/2=4$

  

  $$\left(x,y\right)=\left(\frac{46}{7},\frac{36}{7}\right)$$

• Solve using the Cramer's rule of $x/2+y/3=5,x-y/2=4$

  

  $$\left(x,y\right)=\left(\frac{46}{7},\frac{36}{7}\right)$$

• Determine whether lines are parallel, perpendicular, or neither of $x/2+y/3=5,x-y/2=4$

  

  $$\text{Neither parallel nor perpendicular}$$