begin{arraylx+y+z=62x-y+z=5x+2y-z=3endarray.

Frequently Asked Questions

• Solve using the substitution method of $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the elimination method of $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the Gauss-Jordan method of $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the Cramer's rule of $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$