x + y + z = 6, 2x - y + z = 5, x + 2y - z = 3

Frequently Asked Questions

• Solve using the substitution method of $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the elimination method of $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the Gauss-Jordan method of $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Solve using the Cramer's rule of $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$