Question :
int (2x)/(2x-1)
Evaluate the integral
x+21ln(∣2x−1∣)+C,C∈R
Evaluate
∫(2x−1)2xdx
Remove the parentheses
∫2x−12xdx
Rewrite the expression
∫2×2x−1xdx
Use the property of integral ∫kf(x)dx=k∫f(x)dx
2×∫2x−1xdx
Rewrite the fraction
2×∫(21+4x−21)dx
Use the property of integral ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx
2(∫21dx+∫4x−21dx)
Calculate
2×∫21dx+2×∫4x−21dx
Evaluate the integral
More Steps

Evaluate
2×∫21dx
Use the property of integral ∫kdx=kx
2×21x
Multiply the numbers
More Steps

Evaluate
2×21
Reduce the numbers
1×1
Simplify
1
x
x+2×∫4x−21dx
Evaluate the integral
More Steps

Evaluate
2×∫4x−21dx
Rewrite the expression
2×∫21×2x−11dx
Use the property of integral ∫kf(x)dx=k∫f(x)dx
2×21×∫2x−11dx
Multiply the numbers
More Steps

Evaluate
2×21
Reduce the numbers
1×1
Simplify
1
1×∫2x−11dx
Simplify
∫2x−11dx
Use the property of integral ∫ax+b1dx=a1ln∣ax+b∣
21ln(∣2x−1∣)
x+21ln(∣2x−1∣)
Solution
x+21ln(∣2x−1∣)+C,C∈R
Show Solution
