x^3+y^3=4

Frequently Asked Questions

• $\text{Solve for }x$ of $x^3+y^3=4$

  

  $$x=\sqrt[3]{4-y^3}$$

• $\text{Solve for }y$ of $x^3+y^3=4$

  

  $$y=\sqrt[3]{4-x^3}$$

• Testing for symmetry about the origin of $x^3+y^3=4$

  

  $$\text{Not symmetry with respect to the origin}$$

• Testing for symmetry about the x-axis of $x^3+y^3=4$

  

  $$\text{Not symmetry with respect to the x-axis}$$

• Testing for symmetry about the y-axis of $x^3+y^3=4$

  

  $$\text{Not symmetry with respect to the y-axis}$$

• Rewrite in polar form of $x^3+y^3=4$

  

  $$r=\frac{\sqrt[3]{4}}{\sqrt[3]{{\cos }^3\left(\theta \right)+{\sin }^3\left(\theta \right)}}$$

• $\text{Find the derivative with respect to }x$ of $x^3+y^3=4$

  

  $$\frac{dy}{dx}=-\frac{x^2}{y^2}$$

• $\text{Find the derivative with respect to }y$ of $x^3+y^3=4$

  

  $$\frac{dx}{dy}=-\frac{y^2}{x^2}$$

• $\text{Find the second derivative with respect to }x$ of $x^3+y^3=4$

  

  $$\frac{d^{2}y}{d{x}^2}=-\frac{2x{y}^3+2x^4}{y^5}$$

• $\text{Find the second derivative with respect to }y$ of $x^3+y^3=4$

  

  $$\frac{d^{2}x}{d{y}^2}=-\frac{2y{x}^3+2y^4}{x^5}$$