\text{Solve for }x of \sin\left(x\right)=1\div 2

x=\left\{ \begin{array}{l}\frac{\pi }{6}+2k\pi \\\frac{5\pi }{6}+2k\pi \end{array}\right.,k \in \mathbb{Z}

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Question :

sin(x)=1/ 2

sin (x) = 1 \div 2

x = {\frac{π}{6} + 2 kπ \frac{5 π}{6} + 2 kπ, k \in Z

Alternative Form

x = {3 0^{\circ} + 36 0^{\circ} k 15 0^{\circ} + 36 0^{\circ} k, k \in Z

Alternative Form

x \approx {0.523599 + 2 kπ 2.617994 + 2 kπ, k \in Z

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