\text{Solve for }x of 4^x = 4 \sqrt{3}

x=\frac{4+\log_{2}{\left(3\right)}}{4}

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Question :

4^x = 4 sqrt3

4^{x} = 43

x = \frac{4 + lo g _{2} ( 3 )}{4}

Alternative Form

x \approx 1.396241

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