fractan^{2alpha + 1}sec{alpha} = secalpha

Frequently Asked Questions

• $\text{Solve for }\alpha$ of $\frac{{\tan }^2\alpha +1}{\sec \alpha }=\sec \alpha$

  

  $$\alpha \ne \frac{\pi }{2}+k\pi ,k\in \mathbb{Z}$$

• Verify of $\frac{{\tan }^2\alpha +1}{\sec \alpha }=\sec \alpha$

  

  $$\text{true}$$