Câu hỏi
Find the partial derivative
y2+2ycos(x)+cos2(x)2ysin(x)
Evaluate
∂x∂(y+cos(x)2y)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
(y+cos(x))2∂x∂(2y)(y+cos(x))−2y×∂x∂(y+cos(x))
Use ∂x∂(c)=0 to find derivative
(y+cos(x))20×(y+cos(x))−2y×∂x∂(y+cos(x))
Evaluate
Thêm Bước
Evaluate
∂x∂(y+cos(x))
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂x∂(y)+∂x∂(cos(x))
Use ∂x∂(c)=0 to find derivative
0+∂x∂(cos(x))
Use ∂x∂(cosx)=−sinx to find derivative
0−sin(x)
Removing 0 doesn't change the value,so remove it from the expression
−sin(x)
(y+cos(x))20×(y+cos(x))−2y(−sin(x))
Any expression multiplied by 0 equals 0
(y+cos(x))20−2y(−sin(x))
Evaluate
(y+cos(x))20−(−2ysin(x))
Evaluate
Thêm Bước
Evaluate
0−(−2ysin(x))
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
0+2ysin(x)
Removing 0 doesn't change the value,so remove it from the expression
2ysin(x)
(y+cos(x))22ysin(x)
Giải pháp
Thêm Bước
Use the the distributive property to expand the expression
y×y+ycos(x)+cos(x)×y+cos(x)cos(x)
Multiply the terms
y2+ycos(x)+cos(x)×y+cos(x)cos(x)
Multiply the terms
y2+ycos(x)+ycos(x)+cos(x)cos(x)
Multiply the terms
y2+ycos(x)+ycos(x)+cos2(x)
Calculate
Thêm Bước
Evaluate
ycos(x)+ycos(x)
Collect like terms by calculating the sum or difference of their coefficients
(1+1)ycos(x)
Add the numbers
2ycos(x)
y2+2ycos(x)+cos2(x)
y2+2ycos(x)+cos2(x)2ysin(x)
Hiển thị giải pháp