Solve \sum_{k=1}^7(k^3)

Evaluate

k = 1 \sum 7 k^{3}

Substitute 7 for n into formula i = 1 \sum n i^{3} = \frac{n ^{2} ( n + 1 ) ^{2}}{4}

\frac{7 ^{2} ( 7 + 1 ) ^{2}}{4}

Add the numbers

\frac{7 ^{2} \times 8 ^{2}}{4}

Multiply the numbers

More Steps

\frac{5 6 ^{2}}{4}

Rewrite the expression

More Steps

\frac{8 ^{2} \times 7 ^{2}}{4}

Rewrite the expression

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\frac{2 ^{6} \times 7 ^{2}}{4}

Rewrite the expression

\frac{2 ^{6} \times 7 ^{2}}{2 ^{2}}

Reduce the fraction

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2^{4} \times 7^{2}

Solution

784

Find the sum