Soal-soal Kalkulus Populer
Mengembangkan kemampuan dalam turunan, integral, perhitungan limit, dan masalah optimasi. Memperkuat teknik analitis untuk matematika tingkat lanjut.
- fracddx(2x-5) =
- sum _n=1^infinityfrac1n(n+1)
- lim_x goes to infinity frac |x |x =
- lim_x goes to 2 fracx^{4 - 4 x^3 + 5 x^2 - 4 x + 4}x^{4 - 4 x^3 + 6 x^2 - 8 x + 8} =
- lim_x goes to infinity frac ( 2 x^{4 - 137 )^5} ( x^{2 + 429 )^10} =
- sum_n = 1^infinity n^2
- ( x + 1 ) fracdydx + 2 y = x
- fracdydx + 3 x^2 y = x^2
- fracddx ( x^2 + 2 x + 5 )
- int_e^{2}^e^{3} fracd xx ( ln{x - 1 )}
- int x lnx d x
- ( ln ( x^{2 )} )^prime
- lim _ x goes to infinity frac ( 2 x ^ { 4 - 137 ) ^ 5 } ( x ^ { 2 + 429 ) ^ 10 } =
- lim _ x goes to 2 frac x ^ { 4 - 4 x ^ 3 + 5 x ^ 2 - 4 x + 4 } x ^ { 4 - 4 x ^ 3 + 6 x ^ 2 - 8 x + 8 } =
- lim_x goes to 2 ( fracxx - 3 - frac9x^{2 - 3 x} )
- f(x)=arctan(3x)
- int 1/(y^2)
- int -(1400)/(x^2)
- fracddx ( ln(ax) )
- y=3x
- int -(1600)/(x^2)
- int (200)/(x^3)
- fracddx ( fracx^44 )
- int (te^t)
- int (2x)/(2x-1)
- int x/(1-2x)
- fracddx ( -csc^2(x) )
- fracddu ( frac1u )
- fracddx ( sec^2(2x) )
- int 5x
- fracddy ( ln(3) )
- fracddx ( frac18x )
- fracddtheta ( cos(2theta) )
- int _2^4(y^2-3y+5)
- sum _n=1^infinity frac(-1)^nln n+1
- f(x)=x^3
- y=(x^2+x+1)/x
- y'=x^2,y(0)=2
- lim_xgoes to 0+(fracsin xx)
- int _0^2(3x^2+x-1)
- x^3+y^3=4
- int _ ^ frac1x^2