[(2 Xi^2)^2 4alpha beta]^2=16alpha beta(1 Alpha beta)^2

Введите вашу математическую задачу... [(2-xi^2)^2-4alpha beta]^2=16alpha beta(1-alpha beta)^2

Вопрос

[(2 - x i^{2})^{2} - 4 a lp hab e t a]^{2} = 16 a lp hab e t a (1 - a lp hab e t a)^{2}

Verification required

Please type the verification code shown